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| | #1 |
| Senior Member Join Date: Dec 2001 Location: Redding, CA
Posts: 619
| Quickly anyone, since I forgot.. whats the formula for measuring the distance travelled along an arc? I remember ONE time enroute question on the instrument written that requred using this.. and I just memorized the answer (1hr 20 minutes).. now I wish I knew the formula. |
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| | #2 | |
| Old Skool | Quote:
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__________________ www.flywhiteair.com http://www.myspace.com/desertdog71 Following message is for SkyCougar. ![]() Took my chances on a big jet plane, Never let them tell you that they're all the same. | |
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| | #3 |
| Moderator Join Date: May 2003 Location: GRR
Posts: 8,435
| Well the math isn't too hard, but there may be a shortcut that would give a "close enough" answer - someone else can add that part. To solve the problem you need to know two things: DME distance from the station (or radius if you will), and the number of degrees the arc encompasses. Call the first number "A" and the second number "B". "B" can be calculated by simply subtracting the initial radial from the final inbound course radial (or the other way around depending upon which is the greater number). The distance around a circle is simply (PI x Diameter), thus the distance of a DME arc if you went all the way around (360 degrees) would be (3.1416 x "A" x 2) miles. Since you only travel part way around the circle, we need to take the ratio of the arc compared to the whole circle, which would = "B"/360. Final equation would be: Distance (in miles) = (3.1416)("A")(2)("B")/360 I suppose that you could simplify it and say the length of the arc, in miles, is (0.017453)("A")("B"). Example: DME distance from nav aid = 10 nautical miles ("A") Length of the arc = 60 degrees ("B") <from the 130 degree radial to the 190 degree radial for example>. The length traveled along the arc = (0.017453)(10)(60) = 10.47 nautical miles. If you want to continue on from there and calculate the time required to travel the arc, simply divide the distance by the ground speed. If the plane in the example above was traveling at 120 knots, the time would be 10.47nM/120kts = 0.08725 hours. To change to minutes simply multiply by 60, giving 5.235 minutes, or 5 minutes 14 seconds. I know that isn't the clearest explanation, so if you need further clarification let me know and I'll try to do a better job. ![]()
__________________ . Life is painful. Suffering is optional. |
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| | #4 | |
| Old Skool Join Date: Nov 2005
Posts: 1,648
| Quote:
For a rough answer, you can apply the 60-to-1 rule. As applied to this case, you might recall that at 60 miles from a given station, 1 degree of travel along the arc would amount to approximately 1 NM of travel. Flying around circle of 60NM radius would take approximately 360NM. For this distance, 1 radial = 1 NM For a 20 DME arc, the distance traveled per radial is approximately 1/2 NM. Another method of describing it is 2 radials per NM. A General formula that would cover both of these examples is there are ( 60 / DME ) radials per NM. 20 DME = 3 radials per NM 15 DME = 4 radials per NM 10 DME = 6 radials per NM 120 DME = 1/2 radial per NM Let's say you want to know how many miles you travel when you fly 90 degrees along a given DME arc. In that case, you would take the the number of radials traveled and divide by the radials per NM (from the formula we just found above). On a 60 DME arc: 90 / (1 radial/NM) = 90 NM 30DME: 90 / 2 = 45 NM 10DME: 90 / 6 = 15 NM To combine the two, we'd use this formula Distance traveled along an arc = Radials Travelled / (60 / DME) Do a little algebraic juggling and you can get Distance traveled along an arc = Radials * DME / 60 90 radials, 45 DME => 90 * 45 / 60 = 67.5 40 radials, 12 DME => 40 * 12 / 60 = 8 15 radials, 8 DME => 15 * 8 / 60 = 2 Does any of that help?? . | |
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| | #5 | |
| Old Skool Join Date: Nov 2005
Posts: 1,648
| Quote:
Looks like we posted at the exact same time... well, minute, anyway - - you beat me to the Submit Reply button. I used the approximation given by the 60-to-1 rule, and you used actual trig - - and we see how close they are to each other. Dividing by 60 is the equivalent of multiplying by 0.1666667. I think they're close enough to use. ![]() The bigger lesson to learn here, of course, is that memorizing formulas, or answers, does one little good in the real world. It's far more important to understand the "why"s and "how"s of the world, and be able to figure out answers based on what we know. Both of our posts offered good ways of analyzing the problem and working through to a usable solution. What a concept! ![]() . | |
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| | #6 |
| Moderator Join Date: May 2003 Location: GRR
Posts: 8,435
| See.....I knew there would be a shortcut! For fun, let's apply Tony's rough answer to my example of 10 DME, 60 degrees (or radials). 10DME = 6 radials per NM 60 radials total (190 - 130) Therefore: (60 radials) / (6 radials per NM) = 10 NM 10 is pretty close to 10.47, and a very useful estimate I would say!
__________________ . Life is painful. Suffering is optional. |
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| | #7 |
| Old Skool Join Date: Sep 2001 Location: Inside your OODA loop
Posts: 6,776
| I use the '100 feet per degree per mile' rule-of-thumb. It's the same as Tony's, but I can remember "100 feet per degree per mile". 60 degrees x 10 miles x 100 ft = 60,000 ft = 10 nm This is also useful in the vertical plane, btw.
__________________ Commercial Pilot, ASEL/AMEL/IA Chief Pilot, aerial mapping company -- on furlough Mountain-qualified Search & Rescue/Disaster Relief Mission Pilot, Civil Air Patrol 900+ TT/25 ME B.S., Psychology |
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| | #8 |
| Old Skool | Nice descriptions guys.
__________________ www.flywhiteair.com http://www.myspace.com/desertdog71 Following message is for SkyCougar. ![]() Took my chances on a big jet plane, Never let them tell you that they're all the same. |
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| | #9 |
| Senior Member Join Date: Jan 2006 Location: Wichita, Kansas
Posts: 608
| There is a great book called Mental Math for Pilots by Ronald D. McElroy. It has all the shortcuts for finding distance along an arc, cloud bases, calculating VDPs, etc. You can get it through Sporty's or ASA's website.
__________________ Ryan ATP (CE525, CE510, BE-300), SIC BE-400, CFI, CFII, MEI, IGI |
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| | #10 | |
| Old Skool Join Date: Dec 2005 Location: Winchestertonfieldville
Posts: 6,401
| Quote:
__________________ The simplest answer tends to be correct. | |
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| | #11 | ||
| Old Skool Join Date: Nov 2005
Posts: 1,648
| Quote:
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| | #12 |
| Senior Member Join Date: Dec 2001 Location: Redding, CA
Posts: 619
| thanks for all the replies... now i know why I didnt remember it!! and TonyC, "If the question is distance, 1hr 20 minutes cannot be the answer." thats because it was a Time Enroute question, like I said. Often those questions first require you to figure out distance as an intermediate step ![]() ![]() ![]() And I bet I aint the only pilot who ever memorized something without fully understanding it initially. "65 on short final.. 65 on short final.. my CFI says 65 on short final"TOday I went hiking to clear my brain and I found a HUGE bone laying on the ground.. I think it is a femur of a bear or something like that! Now THAT was more fun to think about than this topic ![]() |
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| | #13 |
| Senior Member Join Date: Dec 2001 Location: Redding, CA
Posts: 619
| ok... I actually found an Instrument Gleim book and found the question. Here is what the FAA uses, and boy there are a LOT LESS digits and formula than the above (posters thank you still): DISTANCE on an ARC = (CHANGE in DEGREES X DME ARC DISTANCE) / 60. phew.. and I was also relieved to see that, in fact, the Time Enroute question that required this calc did have as its answer 1 hour 20 minutes.. ![]() ![]() ![]() |
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| | #14 | |
| Old Skool Join Date: Sep 2003
Posts: 1,846
| Quote:
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| | #15 | |
| Old Skool Join Date: Nov 2005
Posts: 1,648
| Quote:
Distance traveled along an arc = Radials * DME / 60 . | |
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| | #16 | |
| Old Skool Join Date: Nov 2005
Posts: 1,648
| Quote:
I'll correct the typo. Thank you! Hmmmm. It's too late to edit! There goes my legacy.![]() . | |
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| | #17 | |
| Moderator Join Date: May 2003 Location: GRR
Posts: 8,435
| Quote:
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__________________ . Life is painful. Suffering is optional. | |
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| | #18 |
| Old Skool Join Date: Nov 2005
Posts: 1,648
| Hey, if they can change the title of a thread from "A post with 1000 threads" to "A thread with 1000 posts" I think I can survive this little misstep. ![]() Ya ever get the feelin' that your work has gone unappreciated? Here, let me teach you how to do something. No thanks, just give me the formula out of the book - - I don't want to understand it, I just want the answer. <sigh> ![]() . |
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| | #19 | |
| Banned Join Date: Jul 2004 Location: Phoenix, AZ
Posts: 7,329
| Quote:
It was tough growing up in Compton. | |
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| | #20 |
| Junior Member Join Date: May 2003 Location: MO
Posts: 224
| I should probably know this, but why would anybody care what the distance they've gone around a DME arc is? I mean, is there any practical application for this? |
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| | #21 | |
| Old Skool Join Date: Nov 2005
Posts: 1,648
| Quote:
.I don't know what's going on here, but I've tried to use nice paragraphs and all, but it keeps cramming it all together in one little nugget. My apologies for it being difficult to read.... | |
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| | #22 | |
| Junior Member Join Date: May 2003 Location: MO
Posts: 224
| Quote:
![]() I just plug it all into the magic boxes and do what the little green things tell me to ![]() | |
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| | #23 | |
| Old Skool Join Date: Sep 2003
Posts: 1,846
| Quote:
That's good advice TonyC is giving. I don't know what other guys do...but on an instrument arrival...I always look at the distance between stepdown fixes and plan the rate of descent I will need to comply with each one. Most of the time the distance between fixes are right on the 3:1 'typical' descent profile. Sometimes they are not. FWIW, on a dme arc...a procedure i've not flown in ages by the way...I don't use the turn radius formula...but use a rule of thumb. Lead your turn on the arc to intercept the final approach course by a dme that is 10% of your groundspeed. If you're doing 180kts...lead the turn by 1.8 dme. Has always worked for me...and lets me keep as much of my brain power where it needs to be...on flying the gages. If you're like me...where brain power available is close to brain power required...this gets important! | |
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| | #24 | |
| Old Skool Join Date: Sep 2001 Location: Inside your OODA loop
Posts: 6,776
| Quote:
Most modern GPS systems like Ricecake's dual 530s will anticipate the turn and tell him when to begin it, which is why his brain has turned to mush.
__________________ Commercial Pilot, ASEL/AMEL/IA Chief Pilot, aerial mapping company -- on furlough Mountain-qualified Search & Rescue/Disaster Relief Mission Pilot, Civil Air Patrol 900+ TT/25 ME B.S., Psychology | |
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| | #25 |
| Old Skool | Even in the RJ we still use the lead in radial when turning to the final approach course off an arc. Most of our Mexican plates have published lead ins about 10 degrees offset from the final approach course. They work pretty well.....the accuracy of Mexican VOR's on the other hand, well that's a different story. |
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