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| | #51 |
| Agent Smith | If a helicopter is on the surface of a giant elevator descending at 150 fps, the pilot moves the collective to produce a 150 fps climb, will it remain on the elevator, hover, or climb at 150 fps? The same logic applies to the airplane question.
__________________ Doug Taylor http://76school.flyblog.com (old!) http://30west.flyblog.com (updated 11/28) |
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| | #52 | |
| Senior Member Join Date: Oct 2005 Location: KAPA
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uhhhhh what does the speed that the wheels are spinning have to do with anything? Why do you think the airplane isn't going to move just because the treadmill matches the speed? | |
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| | #53 | |
| Senior Member Join Date: Oct 2005 Location: KAPA
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| | #54 | |
| Old Skool Join Date: Sep 2001 Location: San Diego, CA
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| Quote:
BUT! ...........that is a helicopter who's lift is created 100% by it's thrust. It doesn't need relative wind. An airplane needs relative wind. Here's another question: Will an airplane take off with a special humungous fan that creates a tailwind always exceeding it's stall speed? Keep in mind the fan adjusts the wind speed to exceed the airplanes ability to go faster than the relative wind.
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| | #55 | |
| Old Skool Join Date: Sep 2001 Location: San Diego, CA
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| Quote:
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| | #56 |
| Old Skool Join Date: Sep 2001 Location: San Diego, CA
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| Wait a minute... I'm actually thinking right now. The treadmill won't be able to defy the forces of propellar thrust; only the force created by a car's engine propelling a wheel to try to counteract the treadmill's force. Propellar thrust is associated with relative wind (which is at a standstill and not affected by the treadmill) whereas a car wheel is directly affected by the treadmill (because it's directly planted onto it). Since the airplane's wheel is not associated with the counteracting forces of the treadmill, it will takeoff! So basically the only way this would work is if there's the tailwind fan analogy I made above (to counteract against the thrust). Oh man I feel like a dumba$$ lol.
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| | #57 | |
| Moderator Join Date: May 2003 Location: GRR
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__________________ . Life is painful. Suffering is optional. | |
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| | #58 |
| Newbie | Discovery Channel "Myth Busters" here we come!!! |
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| | #59 | |
| Old Skool Join Date: Aug 2004 Location: CFI / CFII in PA
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| | #60 | |
| Old Skool Join Date: Sep 2001 Location: San Diego, CA
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I'm sure it's wheel span is as wide as a treadmill and speed won't exceed the treadmill's speed jk
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| | #61 |
| Old Skool Join Date: Sep 2001 Location: San Diego, CA
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| And here we have a Physics forum discussing the same thing! Good answers... http://forum.physorg.com/index.php?showtopic=2417&st=0 And another forum: http://www.mikeportnoy.com/forum/tm....&key=􆾚
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| | #62 |
| Senior Member Join Date: Oct 2000 Location: Murfreesboro, TN USA
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| One of the posts on that physics forum cracked me up: "Those who think that the airplane will take off are REALLY REALLY freaking ignorants and should not be on this forum."
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| | #63 |
| Old Skool Join Date: Sep 2003
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| I'm not a physics major...but I'll chime in. I'll say the airplane will not fly. My thinking...taxi an airplane up an inclined plane. Use just enough power to keep it stationary...i.e. not rolling backwards. Let's say it takes 2000 rpm just to keep it from rolling back down the inclined plane. The airplane is still stationary...no way it can take off. If the airplane is stationary on the conveyor...and while there's lots of work going on below the wing...there's no work being done on the wing. I see no flying machine in this scenario. |
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| | #64 | |
| Moderator Join Date: May 2003 Location: GRR
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![]() (j/k) Rick Durden talks about this scenario in this week's AvWeb. See his article here. ![]()
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| | #65 | |
| Old Skool Join Date: Sep 2001 Location: San Diego, CA
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| | #66 | |
| Old Skool Join Date: Sep 2003
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Okay the author has lost me with this info [/quote] My comment: Notice that the question does not state that the conveyor's movement keeps the airplane over the starting position relative to the ground, just that it moves in the direction opposite to any movement of the airplane. [/quote] ...so is the airplane advancing forward on the conveyor? If so...this is a poorly worded deal. | |
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| | #67 | |
| Moderator Join Date: May 2003 Location: GRR
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| | #68 |
| Moderator Join Date: Apr 2002 Location: chicago
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| I'll keep this thread in mind next time I take off on a giant converyor belt.
__________________ Yeah, I just stare at my desk; but it looks like I'm working. I do that for probably another hour after lunch, too. I'd say in a given week I probably only do about fifteen minutes of real, actual, work. |
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| | #69 | |
| Senior Member Join Date: Aug 2005 Location: Greenbow
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| | #70 |
| Agent Smith | Might be a good episode for that show "Myth Busters"!
__________________ Doug Taylor http://76school.flyblog.com (old!) http://30west.flyblog.com (updated 11/28) |
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| | #71 | |||
| Senior Member Join Date: Jul 2003 Location: Peeking in your window
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| Quote:
It's not that hard people
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| | #72 | ||
| Senior Member Join Date: Jul 2003 Location: Peeking in your window
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| By some peoples theories, the plane would never move. So if you were coming in to land at 100 mph, on a treadmill going 100mph backwards, would you stop instantly? NOPE! you would continue your normal landing roll excpet your wheels are going twice as fast. Your roll may be shortened by the added friction effects in the wheel bearings, etc but you get the big picture (hopefully)
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| | #73 |
| Old Skool Join Date: Sep 2001 Location: San Diego, CA
Posts: 7,236
| Check this out (stolen from another forum): ![]()
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| | #74 |
| Old Skool Join Date: May 2005 Location: DFW
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| but the conveyer belt is changing its speed in order to keep the plane in the same position. true, if the plane can move forward and produce lift over the wings, enough for takeoff then yes it will get off the ground. however, if the plane does not move forward, which is what i gather from the riddle, then no, it will not take off. |
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| | #75 |
| Senior Member Join Date: Oct 2005 Location: KAPA
Posts: 1,315
| dammit I wish I could edit my post and delete this so it haunts you all for life ![]() |
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