 Re: Vmc and weight
For any given bank angle, the heavier a/c will have a greater horizontal lift component (as mentionned above). That is, the heavier the a/c, the greater the amount of lift that is being produced (lift = weight).
The HCL is what offsets the sideslip during an engine failure so that the sum of forces is 0 and the sum of moments (torques, from a physics standpoint) are also 0. Since the HCL is greater for any given bank angle for the heavier a/c, Vmc will be slightly lower.
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